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Se vuoi un risultato del genere, allora dovresti scrivere così: Dim components() As String components = Regex.Split(",", "1,2,3,4") For i = 0 To components.Length - 1 Log("components-" & i & "=" & components(i)) Next Log:
link: Ho notato un probabile "malfunzionamento" di Regex.Split, ovvero: Dim components() As String components = Regex.Split("", "1234") se non metto il p
link: Anche quello che mi ha suggerito ChatGPT funziona; sostituire il pattern della Regex in questo modo: components = Regex.Split("(?<=.)", "1234") Nota

I usually use Regex.Split because it puts all the fields (substrings) into an array ready for whatever the next processing step is. The .Trim removes leading and trailing spaces. You can just as easily use commas or semicolons or tabs as separators.
link: Is the next step to divide the string, splitting it at each space? What if there are two spaces together? Is there an empty (zero length) field betw
link: If you just wanted a count then you could do: Sub interval(mstr As String) As Int Return Regex.Split(" ", mstr.Trim).Length End Sub

"." is a special char and need to be escaped. Dim Pass2() As String Pass2=Regex.Split("\.","1111.1963") Log("PassSize="&Pass2.Length) For i = 0 To Pass2.Length-1 Log($"Pass ${Pass2(i)}"$) Next
link: B4A 5.8 Salve a tutti come mai questa funzione non va? dove sbaglio? Hello everyone why this function should not be? where am I wrong? Dim Pass2() A
link: thanks solved

See https://en.wikipedia.org/wiki/Regular_expression \n is a special command. I guess you need to escape it. Dim s() As String = Regex.Split("\\n", "test\ncon virgola\ntest split") Log(s.Length)
link: Hi i have stringa="test\ncon virgola\ntest split". How can I apply the split? Dim s() As String = Regex.Split("\n", "test\ncon virgola\ntest split"

CA100 is the SECOND value! Regex starts at the first - to split. means: 1st item is an empty string, 2nd Item CA100, 3rd Item ISTITUTO PERTINI VIA CARPACCIO N° 18 A and 4th item N° 1 CHIAVE MECCANICA Dim strBeforeSplit As String strBeforeSplit="-CA100-ISTITUTO PERTINI VIA CARPACCIO N° 1
link: Hi, How can I split the following string -CA100-ISTITUTO PERTINI VIA CARPACCIO N° 18 A - N° 1 CHIAVE MECCANICA in order to get only -CA100- ? I'm try

That would be regex.split(...) 'or regex.split2(...)

REGEX SPLIT I have found it very difficult to get SPLIT and REGEX generally seems like a complicated thing. You will find following code suggested in several posts to get REGEX functions From here Dim str As String = "This is a test I'm doing to split a sentence into words." Dim RegExp As B
link: At the request of several friends, I opened this Thread which explains some problems encountered when developing with Banano and VuetiiFy. Obviously

Caution with Regex.Split, it ignores trailing empty fields, leaving the number of fields per line short. It is better to use StringUtils.LoadCSV or CSVParser, as @Erel recommended.
link: Downloaded ok ? but I'll leave the deep analysis ? for Albert (I am on a non-programming computer). If you're only reading the data, then I'm still l

Regex will not help here. The string itself is made of two lines. You can disable text wrapping and it will then match the displayed text.
link: I would like to retrieve each line of a textarea. (each line of line wrapping) 74899 > This is my text area i try this code : Dim lines() As Str
link: ok thank you

Man!!! then REGEX.Split is to simple, working in 5 minutes. i've been spending last 3 hours trying to split using all sorts of mid left and right of string. thanks.
link: You could use REGEX.Split to extract each line.

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