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I tried your code and seems fine to me. I get all kind of values for BPM: #, ErrorTime: 1706743178712, DTN: 1706769942615, LastBeatTime: 26763124, BPM: 77, TIM: 779 #, ErrorTime: 1706743177714, DTN: 1706769942617, LastBeatTime: 26763903, BPM: 60, TIM: 1000 #, ErrorTime: 1706743174859, DTN: 170676
link: How about adding RndSeed ? RndSeed(DateTime.Now) BPM_Out = Rnd(1, 101)
link: (rsb.SelectedMaxValue + 1)) BPM_Out = Rnd(1, (100 + 1)) 'Log("BPM: " & BPM_Out) 'End If Catch Log
link: I don't agree. Yes if you set a fixed value RndSeed(36) but No if the value of seed is different every time #If RELEASE Log("== RELEASE ==") #Else L

<JOKE> or the compromise solution: Switchrbtn10cut.Value = Rnd(0, 2) = 1 or the contrarian solution: Switchrbtn10cut.Value = Not(Rnd(0, 2) = 1) Switchrbtn10cut.Value = 1 - Rnd(0, 2) = 1 </JOKE>

(I guess) it is because the original Java (java.util.Random) function already works like this. The function int nextInt(int bound); returns an integer between 0 and bound-1 In order to keep things coherent, the B4A/J function Rnd(min,max) adds 'min' to the result of the above function.
link: I'm sorry, I did not understand (I hope because of my poor English :p). I do not use: Index = rnd (0, List1.Size-1) but Index = rnd (0, List1.Size)
link: haha , u used exact this Index = rnd (0, List1.Size-1) because the parameter name was min and max. for a list i prefer 1 to count but it is as it is.
link: I think it's better this way. If you have a List (or an Array) of N elements, to get one of them: Index = rnd (0, List1.Size) If it were inclusive,

QuarterNumbersTextSize = Rnd(20, 40) ctv1.TimeNumbersTextSize = Rnd(30, 50) ctv1.MarkLineColor = Colors.ARGB(255, Rnd(100, 255), Rnd(100, 255), Rnd(100, 255)) ctv1.MarkSize = Rnd(1,21) ctv1.HighlightMarkLineColor = Colors.ARGB(255, Rnd(100, 255), Rnd(100, 255), Rnd(100, 255)) ctv

Dim random As Int = Rnd(1,5)
link: i found this n = Rnd(1, 4) ' in your case between 1 and 3 ImageView1.Bitmap = LoadBitmap(File.DirAssets, "Image_" & NumberFormat(n, 2, 0) & ".png") Th
link: Dim MyFinalBackgroundImage As B4XBitmap = xui.LoadBitmap(File.DirAssets,"MyImage_" & Rnd(1,5) & ".png")

From the documentation. Rnd(Min As Int, Max As Int) Min inclusive, Max exclusive. Generate a number bertween 1 and 100: N = Rnd(1, 101)

1. Please use CODE tags when posting code here. BTW: Code tags are not using < or >. They need ! correct. to generate a rnd from 1 to 100 you need to call dim r as int = RND(1,101) btw: Due to this the command xc = Rnd(0,Shuffel.Size -1) ' should be xc = Rnd(0,Shuffel.Size)
link: This is probably down to tradition. Random numbers in programming languages has always been like that, either as in B4A, or simply returning a float n
link: This may appear to be a bit strange .....but here we go Documentation: Rnd (Min As Int, Max As Int) As Int Returns a random integer between Min (inc

Rnd(1,101)) SetButtonTextSize(buttonC, Rnd(1,101)) SetButtonTextSize(buttonD, Rnd(1,101)) SetButtonTextSize(buttonB, resultInt) buttonB.Text = resultInt Else if testLevel = 5 Then num1 = Rnd(1,10) 'da un numero random tra 1 e

r = Rnd(2,25) circle.x = Rnd(circle.r,MainForm.RootPane.Width-(circle.r*2)) circle.y = Rnd(circle.r,MainForm.RootPane.Height-(circle.r*2)) overlap = False For j = 0 To circle_list.Size - 1 old_crl = circle_list.Get(j) If distance_x(circle.x,ol

Rnd(min, max) min inclusive and max exclusive, so I assume what emexes means is that it should be Dim idx As Int = Rnd(0, hexValues.Size)
link: This is one part of b4x that I really was not aware of, that 2nd variable being exclusive or will be 1 less. :oops: Fortunately I dont use Rnd often
link: Only because I code algorithms sometimes then I know Rnd and I know almost nothing about your expertise web stuff.. so please no embarrassing at all
link: In case the price of random numbers goes up: Sub RandomHexColor As String Return "#" & Bit.ToHexString(Rnd(0, 0x1000000)).ToUpperCase End Sub an

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