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Locations that are (nearly) antipodal may produce meaningless results. DistanceTo (Dest As LocationF) As Float Returns the approximate distance in meters between this location and the given location. Distance is defined using the WGS84 ellipsoid. HasAccuracy As Boolean Returns true if this location
link: GetLastLocation Wait For (Result As LocationResult) If Result.Status=LocationResult.STATUS_SUCCESSFUL Then Dim Loc As Loc

To get more precise results you could have used the DistanceTo method from the GPS libary. Private Location1, Location2 As Location Location1.Initialize(Lat1, Lng1) Location2.Initialize(Lat2, Lng2) Distance = Location1.DistanceTo(Location2)
link: I read somewhere on the forum that DistanceTo wasn't as accurate, if that's been updated, thats great. I use my function in B4A as well as B4J server,

From the Android documentation for Location.distanceTo https://developer.android..html#distanceTo(android.location.Location) Returns the approximate distance in meters between this location and the given location. Distance is defined using the WGS84 ellipsoid.
link: Sorry, got distracted by football. I tested BearingTo and DistanceTo in B4A this afternoon per post #2, and the results I got agree with agraham - ca
link: I thought they did. Two easy no-math-required tests: What bearing do you get if you travel to a different longitude at the same latitude (other than
link: If your mismatches are small, it might be that one model is using a spherical earth, and the other a fat earth (technical term escapes me, is somethin

Invece di usare "Location.DistanceTo", ti consiglio di usare questo: https://www.b4x..31499/#content questo perchè "Location.DistanceTo" ti da sempre la distanza in linia diretta da un punto all'altro.
link: Ritornando al discorso Distanza autovelox la distanza tra questo e la propria posizione si può fare con Location.DistanceTo(TargetLocation as Android.

Dim l1 As Location l1.Initialize l1.Latitude = 45.1 l1.Longitude = 8 Dim l2 As Location l2.Initialize l2.Latitude = 45.2 l2.Longitude = 8 Log("l1.DistanceTo(l2): " & l1.DistanceTo(l2))

Dim l1, l2 As Location l1.Initialize2(gmap.MyLocation.Latitude,gmap.MyLocation.Longitude) l2.Initialize2(RootMap.Get("LatitudB"), RootMap.Get("LongitudB")) 'ahora necesitamos la distancia entre nuestra ubicación y la ubicación de destino
link: It seems to work, in my tests. private Sub GeoDist(A As Location,B As Location) As Double Dim EarthRadius As Double, PiGrec As Double, X As Doubl

Location.DistanceTo in smaller walking applications using seconds isn't very accurate. The course part of the GPS library works well to identify turns or changes in direction. There are some good examples of heavy math on the forum. They give consistent reliable results. The graphic below uses L
link: The lazy among us are happy with the accuracy of the math-light method of calling Location.DistanceTo and appreciative that it returns SI units too ?
link: Now that you've added that longitudinal adjustment to your solution, I agree. Not sure why you didn't fix the other two issues while you were there.
link: I can vouch for it working great in the southern hemisphere, albeit that is mostly whilst driving. Do you have an example of two (lat, lon) points wh

Sub DistanceTest Dim l1 As Location l1.Initialize l1.Latitude = 0 l1.Longitude = 0 l1.Altitude = 10000 Dim l2 As Location l2.Initialize l2.Latitude = 0 l2.Longitude = 0 l2.Altitude = -10000 Log("l1.DistanceTo(l2): " & l1.DistanceTo(l2)) End Sub
link: I just found this link (just in case if someone else is looking) https://www.b4x.-between-two-gps-points-with-altitude.72072/
link: Hi All Does anyone know if this method takes Altitude into consideration as well? Thanks iCAB

You can create two Location objects (GPS library) and then calculate the distance with Location1.DistanceTo(Location2).
link: Hi I'm make GPS example How can I measure the distance in kilometers between a person and another person? Does it have a keyword? or An example pro

You can use: Distance = CenterLocation.DistanceTo(LocationToCheck) If Distance <= Radius Then ' insides Else ' outsides End If You know the location of your center and you know the locations to check, so can calculate the distance between those with DistanceTo method of the Location object
link: My app for delivery. Can I create an area dependent on longitude and latitude and save it in a database and check the customer's location inside or o
link: What result I get? I changed the center point and radius, I want to check the location inside the circle or not, how? I want a result.

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