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I usually use Regex.Split because it puts all the fields (substrings) into an array ready for whatever the next processing step is. The .Trim removes leading and trailing spaces. You can just as easily use commas or semicolons or tabs as separators.
link: Is the next step to divide the string, splitting it at each space? What if there are two spaces together? Is there an empty (zero length) field betw

To split an image into grids then merge them into a new image. Made in a fast and dirty way so just correct bugs or fit for your own needs with attached source code. I think it could be useful to manipulate game sprite sheet. 138054

'TextField1.Text is empty - just loaded the layout. 'Logs zero. Log("TextField1.Text.Length = " & TextField1.Text.Length) Dim str() As String = Regex.Split(",", TextField1.Text) 'Logs 1 instead of zero. Log("str length = " & str.Length) EDIT: Dim str() As String = Regex.Sp
link: The java string split function returns a string array with one element that contains the original text if there was no match found. And that one elem

From the type documentation, exactly what you want: Split (Pattern As String, Text As String) As String() Splits the given text around matches of the pattern. Note that trailing empty matches will be removed. Example: Dim components() As String components = Regex.Split(",", "abc,def,,ghi") 'returns:

Dim tag As String = $" D.M.I. S.r.l.;DMI S.r.l., azienda giovane nel mondo degli immobili e delle imprese che operano a 360 gradi nel mondo dell'edilizia, che opera con personale d'esperienza nel settore della ristrutturazione e della vendita, sia per privati sia per aziende.;Referente: Sig. Todesch
link: Private Sub (Index As Int) If Index = -1 Then Return Dim lbl As Label = ListView1.Items.Get(Index) Dim record As List record.Initializ
link: ciao e grazie, ma il simbolo dollaro me lo spieghi!!! dovevi spiegarmelo nel 2021 AC ma poi mi sono perso nella sabbia :)

Give this untested thought a burl: array = Regex.Split("(\c\r?|\c?\r)", myText)
link: If the source of myText is a file then File.ReadList accepts different EOL characters. Dim fileLines as List = File.ReadList(sourceDir, "filena
link: I have a b4j application that has to split a text after each line. Now the input files have different control characters at the line end: a) 0x0D 0x0
link: You were quick, very quick and I thank you for that! And yes, splitting worked for the first suggestion. Except that an unnecessary special character

what is SplitText?
link: Dim myans() As String myans = SplitText(File.ReadString(File.DirAssets,"myfile.txt")) EditText1.Text = myans(0)

Regex.Split returns an array. When an array is converted to a List it is only wrapped. It is not copied. It is equivalent to using List.Initialize2: https://www.b4x.com/basic4android/images/SS-2016-05-07_21.27.10.png If you want it to be modifiable then you need to: Dim lstTmp As List lstTmp.Init

The dot has a special meaning in regex. It must be escaped... Dim IpadrressToSplit() As String = Regex.Split("\.", "192.168.0.44") Log(IpadrressToSplit(0)) Log(IpadrressToSplit(1)) Log(IpadrressToSplit(2)) Log(IpadrressToSplit(3))
link: Hii All, I want to split IPAddress, I am using the following code but its not working. Please Help:- Dim IpadrressToSplit() As String = Regex.Split(

or try string function library : Split (CurrentString As String, Split_At_Delimiter As String) As List Returns a LIST of items from the string split at the Delimiter. EXAMPLE: Dim ANS As List ANS = SF.Split("This is a test string.", " ") Dim strSource As String = "-1.4985018,52.4053273,1983688820

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