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Thank you, I did it ! 'open external file USB Storage.OpenInputStream(Storage.FindFile(GetCurrentFolder,filelist)) 'read file TR1.Initialize(File.OpenInput(foldertoload, filelist)) :)
link: Hi DonManfred, the code I was using for internal text file was this: 'open file data TR1.Initialize(File.OpenInput(foldertoload, filetoload))

This is equivalent to: File.OpenInput(Dir, File) 'in ContentChooser event. It has nothing to do with getting a file URI.
link: so? Dim cc As ContentChooser cc.Initialize("cc") cc.Show("*/*", "Select file to be upload.") wait for cc_Result (Success As Boolean, Dir As String, Fi
link: Hey, i found on stackoverflow this thread: https://stackoverflow.com/questions/5657411/android-getting-a-file-uri-from-a-content-uri The first answe

Hola Ángel: ¿Puedes poner las partes de tu código en la que usas archivos a ver si así alguien ve algo raro que te pueda ayudar?
link: Creo recordar que Crashlytics te da también la línea java en la que obtienes el error. Puedes ver los archivos de java en tu carpeta creo recordar que
link: Tengo varios errores en Crashlytics relacionados con ENOENT (No such file or directory) en anywheresoftware.b4a.objects.streams.File.OpenInput, sucede

File.OpenInput returs a wrapperinput, Is there a way to convert it to a FileInputStream?
link: Yes: InputStreamWrapper inw = File.OpenInput(...) InputStream in = inw.getObject();

It is a mistake to try to get a file path from the returned resource. It will not work in most cases, and even if you will be able to get the path, you will not be able to access it. You can use File.OpenInput to access the remote resource. Correct solution: TextEditor - Save and load external fi
link: You don't need to call GetPathFromContentResult if you want to copy the file. You should instead copy the file with: Dim in As InputStream = File.Op
link: Why do you need to file path? The correct way to load such resources is with File.OpenInput.

File.OpenInput has nothing to do with "running" a file. Search for FileProvider and see how the image is displayed with the default viewer app.
link: Dear All I use this code to run "a.pdf" file stored in the device : File.OpenInput(File.DirInternal, "a.pdf") , But it Does not work ! What is the wr

DataFile1.Initialize (File.OpenOutput (File.DirInternal, FileName1, False)) DataFile2.Initialize (File.OpenInput (File.DirRootExternal & "/ Test /", Filename2)) Only Text file
link: Ứng dụng nhỏ của tôi chứa android: targetSdkVersion = "29" và trong tệp kê khai, để đọc và ghi vào thư mục gốc rp.CheckandRequest (rp.) DataFile1.Ini

at java.base/java.io.FileInputStream.open0(Native Method) at java.base/java.io.FileInputStream.open(FileInputStream.java:216) at java.base/java.io.FileInputStream.<init>(FileInputStream.java:157) at anywheresoftware.b4a.objects.streams.File.OpenInput(File.java:225) at

OpenInput(File.DirRootExternal, "/pictures/image_4.jpg") 'bm.Initialize2(in) 'Export the generated bitmap to a PNG and save in in the pictures folder 'Make sure nothing is stuck that should
link: Add(bm) ' 'Dim in As InputStream 'in = File.OpenInput(File.DirRootExternal, "/pictures/image_3.jpg") 'bm.Initialize2(in)
link: Add(bm) ' 'Dim in As InputStream 'in = File.OpenInput(File.DirRootExternal, "/pictures/image_3.jpg") 'bm.Initialize2(in)

io.FileInputStream.open0(Native Method) at java.base/java.io.FileInputStream.open(FileInputStream.java:219) at java.base/java.io.FileInputStream.<init>(FileInputStream.java:157) at anywheresoftware.b4a.objects.streams.File.OpenInput(File.java:218) at anywheresoftware.b4a.objects.stre

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