Italian regex.split - Fulvio75    Dec 4, 2023 Ho notato un probabile "malfunzionamento" di Regex.Split, ovvero:
Dim components() As String
components = Regex.Split("", "1234")
se non metto il pattern la... B4A Question Regex B4A & B4J - LucaMs    Dec 4, 2023 Dim components() As String components = Regex.Split("", "1234") B4A: 5 strings - "" "1" "2" "3" "4" B4J: 4 strings - "1" "2" "3" "4" https://www.b4x.com/android/forum/threads/regex-split.157791/... Bug? [SOLVED] regex.split failure - sorex    Jan 12, 2015 Hello,
for some reason this fails in B4i while it worked fine in B4A.
data=Regex.Split("",num)
num is for example "0200"
it works fine when using 0,2,0,0 & ","... B4A Question regex split pipe doesnt work - techknight    Oct 1, 2020 I am using a pipe | as the delimiter in regex split. But its not working.
any ideas?... B4A Question Regex split - Addo    Jul 7, 2019 i have this following text
dim data as string = "Marten~Samuel~~~Martha~"
dim parser() As String
parser = Regex.Split("\~", data)
i expect to get Length of 5 , but i got Length of 3
why the empty ~ doesn't count in the parser ?... B4J Question regex for split this string:10.8+5-3 - Roberto P.    Jul 4, 2021 can someone help me to extract the rows from the value indicated in the object.
target:
10.8+
3+
5
r... B4J Question Regex.Split with control characters? - techknight    Jul 26, 2018 string/ASCII data.
I was wondering how I could use Regex.Split to separate everything in between... B4A Question RegEx.Split Maintain Case of the Split Elements - Mahares    Apr 27, 2021 .ToLowercase
Dim s() As String =Regex.Split(pat,sentence)
For i=0 To s.Length -1
Log...This works well, but the split elements do not preserve the case.
Dim sentence = "There is NO... Italian regex split - LordZenzo    May 17, 2018 salve, ho fatto un programma per fare un parsing della posta, ad un certo punto devo separare tutto il testo della mail nelle varie parole, per cui uso lo regex.split(" ",testoDaSeparare... B4A Question is regex.split need to be flushed ? - Addo    Mar 13, 2018 .Trim
Dim param As String = msg
Dim paramnum() As String = Regex.Split("\&", param... Page: 1   2   3   4   |