Android Question Casting an object?

[Kevin Golding]

Hello,

I need to pass a ServletResponse object as a Tag in an HttpJob, but I'm not sure how to cast the Tag back to a ServletResponse. Current I'm getting an error saying method SendString not found.

Sub Process_Globals
    Private SRV As HttpServer   
End Sub

Sub Service_Create
    SRV.Initialize("SRV")
    SRV.Start(8282)
    Log("HTTP Server started on port 8282")
End Sub

Sub SRV_HandleRequest(Request As ServletRequest, Response As ServletResponse)
    Log(Request.Method)
    Log(Request.RequestURI)
   
    Dim j As HttpJob
    j.Initialize("HttpJob", Me)
    If Request.Method = "GET" Then
        j.Tag = Response
        j.Download("http://8.8.8.8.8:8282/" & Request.RequestURI)
    End If
End Sub

Sub JobDone(Job As HttpJob)
    Dim Response As ServletResponse = Job.Tag
    Response.SendString(Job.GetString) ` THIS IS WERE I'M GETTING THE ERROR
End Sub

 

[Erel]

Your code looks correct (though you must check that Job.Success is true).
What is the output of:

Log(Job.Tag)
Log(GetType(Job.Tag))

 

[DonManfred]

Your code looks correct

http://8.8.8.8.8:8282/

Calling this url in my PCs brwoser i get an Domain not found....

8.8.8.8 is the DNS from Google

 

[Kevin Golding]

Calling this url in my PCs brwoser i get an Domain not found....

8.8.8.8 is the DNS from Google

I changed the IP in the interest of privacy, and the first IP that came in my head to replace it with was Googles dns server

 

[Kevin Golding]

Your code looks correct (though you must check that Job.Success is true).
What is the output of:

Log(Job.Tag)
Log(GetType(Job.Tag))

I've changed my code to:

Sub JobDone(Job As HttpJob)
    Log("Job: " & Job.tag)
    Log("Job: " & GetType(Job.tag))
    Dim Response As ServletResponse = Job.Tag
    Log("Response: " & Response)
    Log("Response: " & GetType(Response))
    If Job.Success Then
        Response.SendString("SUCCESS") ' ERROR HAPPENS HERE
    Else
        Response.Status = 400
    End If
End Sub

The debug shows:

Job: anywheresoftware.b4a.objects.Servlet$ServletResponseWrapper@a1d7647
Job: anywheresoftware.b4a.objects.Servlet$ServletResponseWrapper
Response: anywheresoftware.b4a.objects.Servlet$ServletResponseWrapper@a1d7647
Response: anywheresoftware.b4a.objects.Servlet$ServletResponseWrapper
Error occurred on line: 52 (REST_Proxy)
java.lang.RuntimeException: Method: SendString not found in: java.lang.Object
    at anywheresoftware.b4a.shell.Shell$MethodCache.getMethod(Shell.java:968)
    at anywheresoftware.b4a.shell.Shell.getMethod(Shell.java:621)
    at anywheresoftware.b4a.shell.Shell.runVoidMethod(Shell.java:750)
    at anywheresoftware.b4a.shell.Shell.raiseEventImpl(Shell.java:343)
    at anywheresoftware.b4a.shell.Shell.raiseEvent(Shell.java:247)
    at java.lang.reflect.Method.invoke(Native Method)
    at anywheresoftware.b4a.ShellBA.raiseEvent2(ShellBA.java:134)
    at anywheresoftware.b4a.BA$2.run(BA.java:328)
    at android.os.Handler.handleCallback(Handler.java:739)
    at android.os.Handler.dispatchMessage(Handler.java:95)
    at android.os.Looper.loop(Looper.java:148)
    at android.app.ActivityThread.main(ActivityThread.java:5417)
    at java.lang.reflect.Method.invoke(Native Method)
    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:726)
    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:616)

 

[Erel]

What happens in Release mode?

 

[Kevin Golding]

What happens in Release mode?

The app doesn't produce an error and continues to run, but my response does not get to the browser. I just get a blank page but I do get a response as the browser doesn't show an error or timeout.

 

[Erel]

The problem is that the response is committed at the end of the HandleRequest event. You cannot later send anything. This means that you cannot send a http request at that point.

Consider implementing a real http server with B4J. It is much more powerful.

 

[Kevin Golding]

The problem is that the response is committed at the end of the HandleRequest event. You cannot later send anything. This means that you cannot send a http request at that point.

Consider implementing a real http server with B4J. It is much more powerful.

But I need to do this on Android. Will I suffer the same if I do it using a TCP socket server on the inbound request?

 

[Erel]

Will I suffer the same if I do it using a TCP socket server on the inbound request?

No.

What are you using HttpServer for? Maybe there are simpler ways.