Android Question Convert number "long" to "hex"

DonManfred

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• Mar 1, 2014

• #2

B4X:

Dim bc As ByteConverter
Dim val(1) As Long
val(0) = 856987458515
Log(bc.HexFromBytes(bc.LongsToBytes((val))))

logs

000000C7886EDBD3

Click to expand...

"Bit" works with an int, not long. But your value doesnt fix to an int
See documentation of Bit.ToHexString

 

Last edited: Mar 1, 2014

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vecino

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• Mar 1, 2014

• #3

Hello, thank you

Then, to convert a long to octal, binary, etc.. What function is used?

Thanks and regards.

 

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DonManfred

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• Mar 1, 2014

• #4

Find out how you can convert each long into INTs
with an int as base you can use the bit-command

Bit.ToBinaryString(intvalue)
Bit.ToOctalString(intvalue)
Dim data() As Byte
data = bc.LongsToBytes(val)

data now hold the single bytes... but i dont know how to convert it to an int which can be used with bit-command.

 

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vecino

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• Mar 1, 2014

• #5

I'm embarrassed to say this, but I do not understand what you said, I used the translate.google and nor understand.


I think it is time for me to learn English

 

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vecino

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• Mar 3, 2014

• #6

I already understood, thanks

 

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S

SPLatMan

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• Jul 22, 2014

• #7

I just tried to wrap the above Long->Hex solution into a sub, but got a weird compile error. So I pasted just the sample code into my sub like so:

B4X:

Sub LongToHexStr(L As Long) As String
    Dim bc As ByteConverter
    Dim val(1) As Long
    Val(0) = 856987458515    '<<<<<<<<<<<
    Log(bc.HexFromBytes(bc.LongsToBytes((Val))))
End Sub

What I get is an error on the highlighted line:

Parsing code. 0.08
Compiling code. Error
Error compiling program.
Error description: Syntax error.
Occurred on line: 2214
Val(0) = 856987458515 '<<<<<<<<<<<
Word: =

Click to expand...

What's wrong with that line? What does

Word: =

Click to expand...

mean?

 

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MaFu

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• Jul 22, 2014

• #8

B4X:

Val[0] = 856987458515

 

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S

SPLatMan

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• Jul 23, 2014

• #9

Thanks MaFu. You mean square brackets? Made no difference. But I did discover the problem after a good night's sleep ... I have a function called Val() elsewhere in my program!

What misled me was that the error message pointed at the line using array variable Val(0). If the declaration had been flagged as Dupe Def then it would have been clearer.

 

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