Android Question Empty strings from EditText

Sub Button1_Click   '.... Log In Button
    Dim job1 As HttpJob
    Username=EditText1.Text
    Password=EditText2.Text
 
    Log(Username)     'Log Output was Correct
    Log(Password)     'Log Output was Correct
 
    job1.Initialize("Job1", Me)
    job1.Download2("http://www.lexiconsoftware.gr/sms/service.asmx/Balance" , Array As String("username",EditText1.Text,"password",EditText2.Text))
End Sub

Sub JobDone (Job As HttpJob)
    Log("JobName = " & Job.JobName & ", Success = " & Job.Success)
    If Job.Success = True Then
        Log(Job.GetString)    ' =  <string xmlns="http://www.lexiconsoftware.gr/">ERR 001 - Invalid username </string>
       '.......................................

Sub Button1_Click
   Username=EditText1.Text.Trim
   Password=EditText2.Text.Trim
   Private errorMessage As String
   Private job As HttpJob
   job.Initialize("", Me)
   job.PostString("http://www.lexiconsoftware.gr/sms/service.asmx/Balance",$"username=${Username}&password=${Password}"$)
   wait for (job) JobDone (job As HttpJob)
   If job.Success Then
       Dim s As String
       s = job.GetString
       Private startIndexSearch As String=$"<string xmlns="http://www.lexiconsoftware.gr/">"$
       Private startIndex As Int=s.IndexOf(startIndexSearch)
       If startIndex>-1 Then
           startIndex=startIndex+startIndexSearch.Length
           Private endIndex As Int=s.IndexOf2("</string>",startIndex)
           If endIndex>startIndex Then
               s=s.substring2(startIndex,endIndex)
               If s.Contains("ERR") Then
                   errorMessage=s
               End If
           Else
               errorMessage="Parse error"
           End If
       Else
           errorMessage="Parse error"
       End If
   Else
       errorMessage="Error: "&job.ErrorMessage
   End If
   job.Release
   If errorMessage.Length>0 Then
       Label3.Text=errorMessage
   Else
       Label3.Text ="Υπόλοιπο " & s
       StartActivity("logged")
   End If
End Sub