Hello there
I am having trouble with encryption. My VB code is below which encrypts some text but I need B4A to encrypt it.. I copied some code from another thread but of course I cannot get it to work as I don't know what needs changing.. can anyone help me please?
and I have this:
Thank you, as always..
Derek.
I am having trouble with encryption. My VB code is below which encrypts some text but I need B4A to encrypt it.. I copied some code from another thread but of course I cannot get it to work as I don't know what needs changing.. can anyone help me please?
B4X:
Private key() As Byte = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24}
Private iv() As Byte = {11, 11, 11, 11, 11, 111, 111, 111} 'Not the real iv
Public Function Encrypt(ByVal plainText As String) As Byte()
Dim utf8encoder As UTF8Encoding = New UTF8Encoding()
Dim inputInBytes() As Byte = utf8encoder.GetBytes(plainText)
Dim tdesProvider As TripleDESCryptoServiceProvider = New TripleDESCryptoServiceProvider()
Dim cryptoTransform As ICryptoTransform = tdesProvider.CreateEncryptor(Me.key, Me.iv)
Dim encryptedStream As MemoryStream = New MemoryStream()
Dim cryptStream As CryptoStream = New CryptoStream(encryptedStream, cryptoTransform, CryptoStreamMode.Write)
cryptStream.Write(inputInBytes, 0, inputInBytes.Length)
cryptStream.FlushFinalBlock()
encryptedStream.Position = 0
Dim result(encryptedStream.Length - 1) As Byte
encryptedStream.Read(result, 0, encryptedStream.Length)
cryptStream.Close()
Return result
End Function
and I have this:
B4X:
Dim kg As KeyGenerator
Dim c As Cipher
Dim B64 As Base64
Dim bconv As ByteConverter
Dim data(0) As Byte
Dim iv(0) As Byte
iv = Array As Byte(11, 11, 11, 11, 11, 111, 111, 111) ' 16 bytes for AES
c.Initialize("DESEDE/CBC/PKCS5Padding")
c.InitialisationVector = iv
kg.Initialize("DESEDE")
kg.KeyFromBytes(bconv.StringToBytes("123456789012345678901234","UTF8"))
data = bconv.StringToBytes(dataToEncrypt, "UTF8")
data = c.Encrypt(data, kg.Key, True)
Return B64.EncodeBtoS(data, 0, data.Length)
Thank you, as always..
Derek.