Find second integer in String

[XverhelstX]

Hello,

I need to get an integer from my string.
I know it is possible with regex, etc but the problem is that I want to have the second integer instead of the first one:

Example with the following string:

Apples 1 (23 apples)

will give me 1, but i need 23.

This is the java code I use in my library:

**
    * Finds an integer in a string.
    * @param findInt
    * @return
    */
   public String findIntegerInString(String findInt) {
      Pattern intsOnly = Pattern.compile("\\d+");
      Matcher makeMatch = intsOnly.matcher(findInt);
      makeMatch.find();
      String inputInt = makeMatch.group();
      return inputInt;
   }

but any other solution is welcome.

Thanks for any help

Tomas

 

[stevel05]

Hi Tomas,

If your string always contains a '(' with the number after it you can use something like:

Sub ParseNumber(FindStr As String) As Int

   StartPos=FindStr.IndexOf("(")+1
   If StartPos <> 0 Then
      EndPos=StartPos
      Do While EndPos < FindStr.Length
         EndPos=EndPos+1
         If FindStr.CharAt(EndPos) = " " OR FindStr.CharAt(EndPos) = "." Then 'Just make sure it's an Int
            Exit
         End If
      Loop
      Num = FindStr.SubString2(StartPos,EndPos)
      If IsNumber(Num) Then Return Num
   End If
   Return -1
End Sub

 

[XverhelstX]

Great Stevel05!

Thanks.

Just what I was looking for!

Tomas

 

[stevel05]

No probs, you may have noticed my error

Do While StartPos < FindStr.Length

Should of course be:

Do While EndPos < FindStr.Length

It wouldn't matter unless the string is not correctly formed!

 

[Erel]

Here is the regular expression solution:

Sub Activity_Create(FirstTime As Boolean)
   Log(GetSecondInteger("Apples 1 (23 apples) "))
End Sub

Sub GetSecondInteger(s As String) As Int
   Dim m As Matcher
   m = Regex.Matcher("\d+[^0-9]+(\d+)", s)
   If m.Find Then
      Return m.Group(1)
   Else
      Return -1
   End If
End Sub