Android Question free panel.loadlayout

[hub73]

Hi !

I use a spinner and a panel to choose a layout to display.

sub spinner_itemclick()

select ...

case "one"
    panel.loadlayout ("one")

case "two"
   panel.loadlayout ("two")

end select

...

end sub

Should i free the previous loaded panel when i load a new .bal ? How to do this ? (clear the previous panel bal below)

Thanks.

 

[johndb]

Hi !

I use a spinner and a panel to choose a layout to display.

sub spinner_itemclick()

select ...

case "one"
    panel.loadlayout ("one")

case "two"
   panel.loadlayout ("two")

end select

...

end sub

Should i free the previous loaded panel when i load a new .bal ? How to do this ? (clear the previous panel bal below)

Thanks.

I would initialize the panel object prior to entering the "select/case" code structure. In that way, you are assured of having a fresh panel.

John

 

[somed3v3loper]

panel.RemoveAllViews
panel.loadlayout ("layoutname")

?

 

[johndb]

panel.RemoveAllViews
panel.loadlayout ("layoutname")

?

panel.initialize ("eventname")
panel.loadlayout ("layoutname")

 

[klaus]

panel.initialize ("eventname")

Oh no.

Sub Spinner_ItemClick()
    Panel.RemoveAllViews
    Select ...
    Case "one"
       Panel.loadlayout ("one")
    Case "two"
       Panel.loadlayout ("two")
    End Select
    ...
End Sub

 

[johndb]

Oh no.

Sub Spinner_ItemClick()
    Panel.RemoveAllViews
    Select ...
    Case "one"
       Panel.loadlayout ("one")
    Case "two"
       Panel.loadlayout ("two")
    End Select
    ...
End Sub

Why not just reinitialize the panel to remove all the previous views and reset the object?

 

[klaus]

Why not just reinitialize the panel to remove all the previous views and reset the object?

Because you initialize each time a new object, the previous ones remain with their layout !

 

[johndb]

Because you initialize each time a new object, the previous ones remain with their layout !

@klaus Thank you for the clarification. I was under the assumption that if you reinitialized an object using the same variable name it wouldn't create a new object but reset the previous object by releasing all of its children (views).

 

[hub73]

Perfect ! Thanks.