Android Question Group records in a List

Are there any criteria for which instance of an id you want?

If not, how about making an empty map. Iterate over the list, and for each value, check if the map contansKey(id); if not, put it

nwhitfield said:

Are there any criteria for which instance of an id you want?

If not, how about making an empty map. Iterate over the list, and for each value, check if the map contansKey(id); if not, put it

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No criteria. Iteration method is slow for a large number of recordings ...although it's probably the only way ...

A couple of questions. Where does the data come from? The list contains strings? If you want to search the data, you would be far better putting it into a SQLite database, then what you want to do is relatively simple.

The data comes from a POST call through HttpJob (a Json string). After deserialization, a List object is obtained. Data from it is going to save the two local tables in SQLLite!

Probably fill the full table first, then fill the second table with the results from an SQL query using the DISTINCT method.

I preferred to change the part of the webserver so that the computing power is superior.

If it were me... and there was 'no way' to get the unique customer ids from anywhere else as part of the web service I would do the following...

Create the Order table as it is.

Then scan the Order table and build a unique customer table.

Actually that's what @stevel05 recommended.

You have to do the first part anyway, the second part is an extra process but a really small one.

How many records are we talking about?

Can you not interrogate the web service to give you just unique customer ids or something? I guess this is outside of your control?