Android Question How do I create a ColorDrawable Designer property for a CustomView?

Widget

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My CustomView has two panels, the default panel and an embedded panel.
The embedded panel needs to have its own ColorDrawable property and I'd like to have this ColorDrawable property accessible in the Designer.

This is what I'd like to have:
B4X: 
#DesignerProperty: Key: EmbedDrawable, DisplayName: Embed Drawable,  FieldType: ColorDrawable, DefaultValue: NULL, Description: The ColorDrawable for the embeded panel

But B4A doesn't accept "FieldType: ColorDrawable" as a field type for a DesignerProperty.

Is there a solution?

TIA
 
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Widget

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klaus said:
Have you tryed simply: FieldType: Color
Click to expand...

Oops. I should have said I wanted a Designer property similar to Base Background > Drawable which gives me the options of ColorDrawable, GradientDrawable and BitmapDrawable. See picture.

I could create 4 individual properties for GradientDrawable, namely CornerRadius, Orientation, FirstColor and SecondColor. But before I do that I was wondering if there is a predefined property type that I could use.

TIA
 

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Widget

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Erel said:
I guess that you are already using the "base background" property for the first panel, right?
Click to expand...

Correct

Erel said:
If so then you will need to add the four properties and create the ColorDrawable in your code. There is currently no ColorDrawable field type.
Click to expand...

I was afraid of that. I will use the 4 individual properties as suggested.
 
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