B4J Question How do I get the numeric value of a string?

S

sorex

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• Mar 25, 2017

• #2

just dim your destination (num) as int

in some cases you might need parseInt

 

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EnriqueGonzalez

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• Mar 26, 2017

• #3

i do not know VB6 but B4J.

you may use:

B4X:

if isnumber("123456") then
'This will work.
dim num as int = "123456"
end if

now that i think of it. B4x language easiest the transformation for strings and integers, in JAVA that would be impossible to do.

 

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Erel

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• Mar 26, 2017

• #4

sorex said:

in some cases you might need parseInt

Click to expand...

Only needed if the number is not in base 10.

 

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S

sorex

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• Mar 26, 2017

• #5

or when doing math without the need to create extra variables.

 

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Erel

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• Mar 26, 2017

• #6

sorex said:

or when doing math without the need to create extra variables.

Click to expand...

Example?

Strings are allowed:

B4X:

Log("45" + "23") '68

 

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S

sorex

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• Mar 26, 2017

• #7

sure, when working with string seperations it sometimes doesn't work as expected while it works fine with regex.

B4X:

Dim txt="12345"
Log(5*txt.CharAt(3))  <- doesn't compile
Log(5*Bit.ParseInt(txt.CharAt(3),10))  <- works fine

using an extra int variable is the workaround ofcourse.

 

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Erel

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• Mar 26, 2017

• #8

Chars are not converted to numbers automatically. You can use your code or you can convert it to string with:

B4X:

Log(5 * ("" & txt.CharAt(3)))

 

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S

sorex

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• Mar 26, 2017

• #9

indeed, thanks for the hint!

 

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Mikelgiles

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• Mar 26, 2017

• #10

Thanks guys. Sometimes I just need to remember that just because VB6 needs something doesn't mean that B4J does. Sometimes it is easier to figure out the hard things than it is to figure out the easy things! I like that the VAL function is not needed and it makes perfect sense.

 

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