how to add dip with variables

NJDude

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• May 23, 2012

• #2

Like this:

B4X:

dim leftedge as int
leftedge=112dip

 

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A

Aysic4Bandroid

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• May 23, 2012

• #3

ok,
should have tried it first, i did it but didnt run it cos it kind of looks so wrong like concatenating an int to a string

thanks for that, NJDude

 

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Erel

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• May 24, 2012

• #4

You can also apply the dip unit to a variable directly:

B4X:

Button1.Left = SomeVar * 1dip

 

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M

Mike Henry

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• Mar 8, 2013

• #5

I don't know if anyone is still reading this old thread, but I'd like to add a comment.
It appears DIP returns an integer, so if DIP is 0.9 then 1DIP will return 0.
The only way I got DIP to work with a variable is to convert it to a double before hand.
Like this:

B4X:

   Dim dipf As Double
   dipf = 100dip / 100
   V.Left = ReScale(N) * dipf

 

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klaus

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• Mar 8, 2013

• #6

You could use:

B4X:

V.Left = DipToCurrent(ReScale(N))

Best regards.

 

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Erel

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• Mar 9, 2013

• #7

@Mike you are correct. The code I posted in post #5 is wrong. It should have been:

B4X:

Button1.Left = SomeVar * 100dip / 100

 

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