V vercettyDev Active Member Licensed User Longtime User Aug 1, 2018 #1 I am trying to open accessibility permissions exactly in my application. What am I doing wrong ? Last edited: Sep 30, 2022
Erel B4X founder Staff member Licensed User Longtime User Aug 1, 2018 #2 Where does this code come from? It cannot work as there is no such activity. Upvote 0
V vercettyDev Active Member Licensed User Longtime User Aug 1, 2018 #3 I'm using this set component But I wanted to open directly in my application so the client did not get looking for the application. Last edited: Sep 30, 2022 Upvote 0
I'm using this set component But I wanted to open directly in my application so the client did not get looking for the application.
DonManfred Expert Licensed User Longtime User Aug 1, 2018 #4 Amanda Sura said: But I wanted to open directly in my application so the client did not get looking for the application. Click to expand... 1. I don´t think this is possible, The User must select your app. Amanda Sura said: DoAction.SetComponent("com.android.settings/.accessibility.b4a.example") Click to expand... 2. You REALLY should change your packagename. All new apps build with B4A will have this packagename. You should use your own packagename. ALWAYS. Upvote 0
Amanda Sura said: But I wanted to open directly in my application so the client did not get looking for the application. Click to expand... 1. I don´t think this is possible, The User must select your app. Amanda Sura said: DoAction.SetComponent("com.android.settings/.accessibility.b4a.example") Click to expand... 2. You REALLY should change your packagename. All new apps build with B4A will have this packagename. You should use your own packagename. ALWAYS.
moster67 Expert Licensed User Longtime User Aug 1, 2018 #5 As @DonManfred said, it is not possible. Upvote 0
peacemaker Expert Licensed User Longtime User Dec 27, 2019 #6 B4X: Dim i As Intent i.Initialize("android.settings.ACCESSIBILITY_SETTINGS", "") StartActivity(i) Upvote 0