Problem: conversion of a variable

Hello,

I have got a little problem concerning the conversion of a variable. I get different results if I run the following code on my pc and on my mobile phone:

Dim test As String
Dim test2 As Number

DateFormat("dd.mm.yyyy")
test = DateParse("01.01." & DateY)
Msgbox(test)
test2 = DateParse("01.01." & DateY)
Msgbox(test2)

Click to expand...

I get the following messages on my pc:
"633979008000000000"
"6.33979008E+17"

On my phone on the other hand twice I get the message:
"6.33979008E+17"

Is there any way that I also can get the result "633979008000000000"? Or is it just a problem with my mobile phone. I need this information ("01.01." & DateY) for a sql statemtent. I would like to avoid converting "6.33979008E+17" to "633979008000000000".

I have already searched through the forum but I could not find anything. Sorry if this question has been asked and answered in the past.

Thanks in advance for any help.

EDIT:
One line missing in the code at the top --> DateFormat("dd.mm.yyyy")

Hi, on device you can't show more than 9 digits after the dot (Like in JavaScript and other), the better way is to round your number to 9 digits:

test=Round(test,9)

Maybe I'm wrong...

Edit:
Sorry I didn't well see:
You can use the SubString() function and keep only 9 digits...
test=SubString(test,0,9)

Thank you for the answer. But unfortunatly i can't round at that point. I need the exact value for the following code:

...
date = DateParse("01.01." & DateY)
Command.SetParameter("date", date)
Command.CommandText = "UPDATE termin SET vereinbart=0, absolviert=0 WHERE (vereinbart=1 OR absolviert=anzahl) AND date<@date"
...

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The result is that the sql statement does not update any records. This works on the pc because it has the correct value in @date. This is why I also can't use SubString().

You will probably find that if you compile it on the desktop you will also get the scientific notation when the ticks are converted to string - which is what is happening when you use MsgBox. To format the string the way you want use

Format(test, "F0")

sitajony said:

You can use the SubString() function and keep only 9 digits...

Click to expand...

Which of course totally ruins the ticks value of the date.

danbiff said:

"633979008000000000"
"6.33979008E+17"

Click to expand...

These are just different representations of the same value (as counting the digits will show.

Using the Format(test, "d1") function should render the value as a strict integer if required. Unfortunately I tried it and it gives a wrong (negative!) answer. Deeper into bug territory?

Mike.

agraham said:

Format(test, "F0")

Click to expand...

That did the trick. Thank you.