Hello
I have a hex string - 0C60EB5C87824A355D50C2FCC9F30768CFBB45AC9BCFA1 - I want to decode each hex value back it int value.
Original vb6 Code :
The above show the original output from VB6 and the output from B4J. 3rd byte in different in B4J
Is the a better way to do this so I get the same result as the vb6 function ?
Any help would be appreciated
Regards
John.
I have a hex string - 0C60EB5C87824A355D50C2FCC9F30768CFBB45AC9BCFA1 - I want to decode each hex value back it int value.
B4X:
public Sub hex_decode(pData As String) As String
Dim x As Int, res As String, h As String, d As Int, b(1) As Byte, c As String
Log("hex_decode :pData len = " & pData.Length)
Try
For x = 0 To (pData.Length-1) Step 2
' // get hex byet
h = su.Mid(pData, x, 2)
' // get int value
b(0) = Bit.ParseInt(h,16)
c = bc.StringFromBytes(b,"WINDOWS-1251")
Log(h & " " & b(0) & " " & Asc(c))
res = res & c
Next
Catch
res = ""
End Try
Log(res)
Log("hex_decode :res len = " & res.Length)
Return res
End Sub
Original vb6 Code :
B4X:
Function hex_decode(pData As String) As String
Dim x As Integer, res As String
On Error GoTo jmp99
For x = 1 To Len(pData) Step 2
res = res & Chr(CInt("&H" & Mid(pData, x, 2)))
Next x
jmp99:
If Err.Number <> 0 Then
hex_decode = pData
Else
hex_decode = res
End If
End Function
The above show the original output from VB6 and the output from B4J. 3rd byte in different in B4J
Is the a better way to do this so I get the same result as the vb6 function ?
Any help would be appreciated
Regards
John.