Android Question Rnd problem/question

[alienware40]

Hi,

I have sort of a problem when using rnd function.

Rnd(0, 10) will get me any random number between 0 and 9, but can I somehow exclude for example number 7?

Thanks a lot,
Leon.

 

[mangojack]

there might be a more elegant way .. but for a simple fix ..

Dim rndNum As Int
     rndNum  = Rnd(1, 10)  ' Create random number. 1 to 9

   Do While rndNum = 7     ' Do not accept #7
     rndNum = Rnd(1, 10)
  Loop

  Log (rndNum)

 

[Straker]

Hi,

I have sort of a problem when using rnd function.

Rnd(0, 10) will get me any random number between 0 and 9, but can I somehow exclude for example number 7?

Thanks a lot,
Leon.

    Dim x As Int
    x=7
    Do Until x<>7
        x=Rnd(0,10)       
    Loop

Unfortunately B4A doesn't have a DO / LOOP UNTIL construct.
If someone knows a better way to write this code, it will be appreciate.

 

[Mahares]

@Straker: mangojack already offered the correct solution and a better way to write the code.

 

[Straker]

@Straker: mangojack already offered the correct solution and a better way to write the code.

Ok, I was writing the answer, and in the meantime mangojack was posting his.

 

[derez]

x=Rnd(0,9)
if x > 6 then x = x+1

 

[Troberg]

x=Rnd(0,9)
if x > 6 then x = x+1

No, no, no. That would give 7 a twice as high probability as the other outcomes.

 

[mc73]

x=Rnd(0,9)
if x > 6 then x = x+1

No, no, no. That would give 7 a twice as high probability as the other outcomes.

Why? From what I see in Derez's code, we have 9 outcomes (0->8) with equal probability. Adding 1 when >6, just transposes in order to avoid 7.

 

[Troberg]

Of course, you are correct. That's what one gets for not reading properly...