Android Question start an app with startactivity

[tmtube73]

good morning everyone, i should start an app with startactivity, my app is called "means" i tried to call the command

StartActivity ("means")

but it doesn't work, is there a way to know what to write in parentheses to start a certain app installed in the phone?

 

[Erel]

Please use [code]code here...[/code] tags when posting code.
The correct way is to pass the activity name directly:

StartActivity(Means)

Note that starting from Android 10 it will not work if the app is in the background unless you request the special draw over other apps permission.

 

[tmtube73]

i tried to run this sub but it stops the app and does not open the other app

Sub ApriMezzi

    Dim In As Intent
    In.Initialize("","")

    In.SetComponent("appinventor.ai_myname.myapp/.Screen1")    '<-- for instance "b4a.example/.main"

    Dim FLAG_DISMISS_KEYGUARD As Int = 0x00400000
    Dim FLAG_TURN_SCREEN_ON As Int   = 0x00200000

    In.Flags = Bit.Or(FLAG_TURN_SCREEN_ON, FLAG_DISMISS_KEYGUARD )
 
    StartActivity(In)

End Sub

 

[Erel]

I didn't understand that you want to start another app.

The best way is to get the intent with PackageManager.GetApplicationIntent.

 

[tmtube73]

debugging the line

StartActivity(In)

I got this error message

Error occurred on line: 112 (Starter)
android.content.ActivityNotFoundException: Unable to find explicit activity class {appinventor.ai_amorosik4.MEZZI/appinventor.ai_amorosik4.MEZZI.Screen1}; have you declared this activity in your AndroidManifest.xml?

 

[tmtube73]

yes i want to open an app made with external app inventor named "mezzi" i know the package and i know the name of the first screen of the app which is Screen1

 

[Erel]

See my previous answer.

 

[tmtube73]

I seem to have guessed that I have to declare my activity in the android manifest file?

I saw your message before but the app I have to follow is an app developed in the appinventor

 

[Erel]

It doesn't matter how the other app was developed. Search for GetApplicationIntent.

 

[tmtube73]

it gives me a compilation error, but I have already selected the phone library

B4A Version: 9.80
Java Version: 11
Analysis of the Code. (0.00s)
Building folders structure. (0.01s)
Compiling the code. error
Error in compiling the program.
Error description: The current declaration does not correspond to the previous one.
Previous: {Type = Phone, Rank = 0, RemoteObject = True}
Current: {Type = PackageManager, Rank = 0, RemoteObject = True}
Line error: 87
Dim p As PackageManager

 

[Erel]

The error message is accurate. Carefully read it.

You have another 'p' variable which is declared as a Phone object. Change the second one to 'pm'

 

[tmtube73]

I also tried this way, but by debugging the message that intent1 is not initialized, can someone help me understand?

    Dim Intent1 As Intent
    Dim pm As PackageManager
    Intent1 = pm.GetApplicationIntent("appinventor.ai_miapp.appname")
    'Dim Packages As List
    'Packages = pm.GetInstalledPackages
    'For i = 0 To Packages.Size -1
    ' Log(Packages.Get(i))
    'Next
    Try
        StartActivity(Intent1)
    Catch
        ToastMessageShow("Cannot start file. " & CRLF & "appname", False)
    End Try

 

[Erel]

1. You should post the error message.
2. If intent1 is not initialized then the package name is probably incorrect.