Android Question Stop a ringtone

sixvoz · May 29, 2016

Hi, can someone give me info and sample on how stop a ringtone?

B4X:

   Dim jo As JavaObject
   jo.InitializeStatic("android.media.RingtoneManager")
   Dim jo2 As JavaObject
   jo2.InitializeContext
   Dim u As Uri
   u.Parse(rm.GetDefault(rm.TYPE_RINGTONE))
   ringtone =jo.RunMethodJO("getRingtone", Array(jo2, u))
   'jo.RunMethod("stopPreviousRingtone", Null)
   ringtone.RunMethod("stop", Null)

This Not stop the ringtone.

Help please.

Thank you.

Erel · May 30, 2016

Where is the code that plays the ringtone?

sixvoz · May 30, 2016

B4X:

Dim rm As RingtoneManager
.
.
.
.

rm.Play(rm.GetDefault(rm.TYPE_RINGTONE))

DonManfred · May 30, 2016

I guess it must be something like (but i can be wrong)

B4X:

dim rt as JavaObject
rt = rm.GetDefault(rm.TYPE_RINGTONE)
[...]
rt.play
rt.stop

sixvoz · May 30, 2016

DonManfred said:
rt.play

Unknown member play

Erel · May 30, 2016

You must play it by calling ringtone.RunMethod("play", Null).

KMatle · May 30, 2016

sixvoz said:
Dim jo As JavaObject
jo.InitializeStatic("android.media.RingtoneManager")
Dim jo2 As JavaObject
jo2.InitializeContext
Dim u As Uri
u.Parse(rm.GetDefault(rm.TYPE_RINGTONE))
ringtone =jo.RunMethodJO("getRingtone", Array(jo2, u))
'jo.RunMethod("stopPreviousRingtone", Null)
ringtone.RunMethod("stop", Null)

Just use only

B4X:

ringtone.RunMethod("stop", Null)

Important: Must be the same ringtone object which started the ringtone to play (NOT a new instance which you have created here).

sixvoz · May 30, 2016

Thank you very much, already it works quite perfectly.

Android Question Stop a ringtone

sixvoz

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Erel

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Erel

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KMatle

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