B4R Question uint8_t & uint16_t

[Siam]

hello,

how can i convert an uint to uint8_t or uint16_t in b4r ?

i have the following command:

getchar (c as uint8_t, size as uint_8t , buff as uint8_t) as uint8_t

this funktion i will call

uint8_t getChar(uint8_t c, uint8_t size, uint8_t *buf);

this is in my .h file

uint8_t getChar(uint8_t c, uint8_t size, uint8_t *buf);

this is my .cpp file

    uint8_t B4RMDMAX72xxLedMatrix::getChar(uint8_t c, uint8_t size, uint8_t *buf){
    return led->getChar(c, size, *buf);
    }

how can i call this command ?

regards

Andy

 

[Erel]

uint8_t is the same as Byte.
uint16_t is the same as UInt.

 

[Siam]

then i make something wrong

 Cannot cast type: {Type=Byte,Rank=0, RemoteObject=True} to: {Type=uint8_t,Rank=0, RemoteObject=True}

 

[Siam]

ok sometimes i should take a break ... now i have it thx