Android Question Weird multiplication error

[rafaelmotaquintana]

Does anybody know why this code returns 1019.99 ?

Log("Res : " & (10.20 * 100))

 

[Star-Dust]

Floating point calculations have a "rounding" that is not very accurate and therefore sometimes generates these errors.

 

[rafaelmotaquintana]

I see. I need to save the value 10.20, as 1020, but I always get 1019.
Any code to do this correctly?
Thanks

 

[Star-Dust]

Dim V As Float = 10.20
Dim S As String = V
S=S.Replace(".","")
Log(s)

or

Dim V As Float = 10.20
Dim S As String = V
Dim I As int = S.Replace(".","")
Log(i)

OR

Sub Activity_Create
   Dim V As Float = 10.20
   Log(MakeInt(v))
End Sub

Sub MakeInt(N As String) As int
   Dim I As int
   I=N.Replace(".","")
   Return I
END Sub

 

[MarcoRome]

    Log("Res : " & Round(10.20 * 100))

 

[Star-Dust]

also

Log("Res : 1020")

 

[Erel]

NumberFormat / NumberFormat2 / smart string are the preferred methods to convert a number to string.

Log($"Res : $1.0{10.20 * 100}"$) 'will print 1,020 ($1.0 means: minimum 1 integer, maximum 0 fractions)
Log($"Res : ${NumberFormat2(10.20 * 100, 1, 0, 0, False)}"$) 'will print 1020

 

[rafaelmotaquintana]

Numberformat2 did it well . Thanks