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If you write: listB.AddAll(listA) The contents of listA is added to the contents of listB. The clear method removes all the items from the list (listB) So now listA remains the same!
link: Sub Process_Globals Private fx As JFX Private MainForm As Form Private listA As List Private listB As List End Sub Sub AppStart

i don't fully agree with the selections on the list, but i would use regex.split() and list.addall(). i'm guessing the string uses crlf (or possibly "\r\n", depending). so split the string on crlf to get an array of strings and then create a list and call addall. dim result as string = job.getstrin

newlist.As(List).AddAll(l) this snippet should return already a declared list named newlist with all items added from list "l" ITS A WISH!!
link: i would like this to work without declaring the object newlist newlist.As(List).AddAll(l) Log(newlist.Size) code that is needed now Dim
link: yes this solution is good to create a new list but not to copy 1 list to another. if i want to copy 1 list to a second list i will need to initialize
link: Unless you need to later add or remove elements: Dim newlist As List = Array("aa", "bb") In other cases, you can add a sub that creates the object

This works: Dim lst As List lst.Initialize lst.AddAll(File.ListFiles(File.DirDocuments)) lst.Sort(True) Log(lst)

Hi: Without knowing why the error is produced (and that's probably what you want to know, instead another solution), have you tried with: AddAll (List As List) Adds all elements in the specified collection to the end of the list. Note that you can add an array directly. Example: List.AddAll(Array
link: File.ListFiles returns a read-only list (see the help box). AddAll will indeed work: Dim List1 As List List1.Initialize List1.AddAll(File.ListFiles(
link: Yes, I knew that thx, but it needed to add a suffix to each filename. AddAll did not work if I tried to do it to the list returned by listfiles. But

You are welcome. AND there is an even more "simpler" but not so practical way. if the number of list is known you can create something like this: Sub AppStart (Form1 As Form, Args() As String) MainForm = Form1 MainForm.SetFormStyle("UNIFIED") 'MainForm.RootPane.LoadLayout("Layout1") 'Load the la
link: MainForm.Show Dim list1 As List : list1.initialize Dim list2 As List : list2.initialize Dim list3 As List : list3.initialize list1.AddAll( Array As
link: What's the easiest way, in B4J, to refer to an element in a nested list? So specifically, if you had List1.AddAll( Array As String( "one", "two", "f

Quiz: What is the difference between: Dim MyList As List MyList.Initialize MyList.AddAll(Array ("no", "yes","ooo","test","yyy","nnn")) And: Dim MyList As List = Array ("no", "yes","ooo","test","yyy","nnn") ?
link: If we are tabulating the number of ways, here is another: Dim MyList As List MyList.Initialize MyList.AddAll(Array ("no", "yes","ooo","test","yyy","nn

Yes you can: Sub keywordsCloud Dim lst As List lst.Initialize lst.AddAll(Array As String("Erel","B4X","Hamied","Newyork","Sana'a","Dubai","ykucuk","toby","Egypt","Frankfourt","Erel","B4X","Hamied","Newyork","Sana'a","Dubai","ykucuk","toby","Egypt","Frankfourt")) For i=0 To lst.Size-1

Here you have created a list and are feeding it items by setting its data bindings to "listitems". This expects a list of objects. This can either be a key value map list or just a simple list. For example in the ViewInputDialog page in the tutorial, we defined a list using key value pairs 'R3
link: I've been thinking about the proper solution for this. Here is my proposed solution 1. Convert ALL your data sources for ALL your selects to key valu
link: Hello! I have a page with a list. I set the event on click for this list because i want to set the state on Select and on TextFields: Dim set1 As Vu
link: Yes, there is a safe method, and you had already started to implement it. In your case, you want to update a select records when a list item is click

Here you go @Arf. Below is an example of a list. I would read your values from a database if possible though. 'Example Dim Listy As List Listy.Initialize Listy.AddAll(Regex.Split(", ", "3.0, 1.3876, -0.0221, -0.0832, 3.25, 1.2621, -0.0191, -0.0616, 3.5, 1.1460, -0.0167, -0.0420"

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