D Dey Active Member Licensed User Longtime User Jul 25, 2025 #1 ProgressDialog.ShowDialog($"LINE 1... LINE 2..."$) Isn't this supported? Thanks for your reply.
Solution aeric Jul 25, 2025 Dey said: ProgressDialog.ShowDialog($"LINE 1... LINE 2..."$) Isn't this supported? Thanks for your reply. Click to expand... You can set the internal label to multi-line. B4X: Dim pd As B4XProgressDialog pd.Initialize(Root) pd.Label1.As(Label).SingleLine = False pd.ShowDialog($"LINE 1... LINE 2..."$)
Dey said: ProgressDialog.ShowDialog($"LINE 1... LINE 2..."$) Isn't this supported? Thanks for your reply. Click to expand... You can set the internal label to multi-line. B4X: Dim pd As B4XProgressDialog pd.Initialize(Root) pd.Label1.As(Label).SingleLine = False pd.ShowDialog($"LINE 1... LINE 2..."$)
aeric Expert Licensed User Longtime User Jul 25, 2025 #2 Dey said: ProgressDialog.ShowDialog($"LINE 1... LINE 2..."$) Isn't this supported? Thanks for your reply. Click to expand... You can set the internal label to multi-line. B4X: Dim pd As B4XProgressDialog pd.Initialize(Root) pd.Label1.As(Label).SingleLine = False pd.ShowDialog($"LINE 1... LINE 2..."$) Last edited: Jul 25, 2025 Upvote 0 Solution
Dey said: ProgressDialog.ShowDialog($"LINE 1... LINE 2..."$) Isn't this supported? Thanks for your reply. Click to expand... You can set the internal label to multi-line. B4X: Dim pd As B4XProgressDialog pd.Initialize(Root) pd.Label1.As(Label).SingleLine = False pd.ShowDialog($"LINE 1... LINE 2..."$)
aeric Expert Licensed User Longtime User Jul 26, 2025 #4 Actually you should mark the previous post (post #2) above but never mind. Upvote 0
aeric Expert Licensed User Longtime User Jul 27, 2025 #5 Thanks Erel for marking the answer as solution. Upvote 0
D Dey Active Member Licensed User Longtime User Jul 27, 2025 #6 Sorry, you're right! I got a little confused... Thanks Upvote 0