Android Question Combine two patterns in the same edit text: csbuilder

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Pathrose

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Licensed User
Hi.
Referring to this example https://www.b4x.com/android/forum/t...ing-based-on-regex-pattern.83002/#post-525565
I would like to color two words in the same edit text with two different patterns. But when I apply the above example only one pattern works..how do I combine two patterns in the same edit text field
Regards...Here is my code
B4X: 
Dim s As String = edtDose.Text

    Dim cs As CSBuilder = MarkPattern(s, "\B(℗\w+)\b", 1)

    edtDose.Text = cs

Dim y As String = edtDose.Text

   Dim cs As CSBuilder = MarkRoute(y, "\B:)\w+)\b", 1)

    edtDose.Text = cs
 
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drgottjr

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Longtime User
you are overwiting the first string with the second. with csbuilder, you add each successive string to the builder. when you're done building, you call builder.toString.
B4X: 
dim cs as csbuilder
cs.initialize
cs.append(MarkPattern(s, "\B(℗\w+)\b", 1) ).append( MarkRoute(y, "\B:)\w+)\b", 1))
edtdose.text = cs.tostring
 
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P

Pathrose

Member
Licensed User
Thank you for your reply..
It is repeating the the edtDose.text without any effect..below is my complete code
B4X: 
Dim s As String = edtDose.Text

Dim cs As CSBuilder = MarkPattern(s, "\B(℗\w+)\b", 1)

edtDose.Text = cs

Dim y As String = edtDose.Text

Dim cs As CSBuilder = MarkRoute(y, "\B:)\w+)\b", 1)

edtDose.Text = cs


Sub MarkPattern(Input As String, Pattern As String, GroupNumber As Int) As CSBuilder

    Dim cs As CSBuilder

    cs.Initialize

    Dim lastMatchEnd As Int = 0

    Dim m As Matcher = Regex.Matcher(Pattern, Input)

  

    Do While m.Find

        Dim currentStart As Int = m.GetStart(GroupNumber)

        Log(GroupNumber)

        Log(currentStart)

        cs.Append(Input.SubString2(lastMatchEnd, currentStart))

      

        Dim AA As String = Input.SubString2(lastMatchEnd, currentStart)

        Log(AA)

        lastMatchEnd = m.GetEnd(GroupNumber)

        Log(lastMatchEnd)

          

      

        'cs.Bold.Underline

        cs.Underline

        'cs.Color(0xFFEE82EE)

        cs.Color(0xFF4169E1)

        cs.Clickable("cs", m.Group(GroupNumber))

        cs.Append(m.Group(GroupNumber))

        'cs.Pop.Pop.Pop.Pop 'number should match number of stylings set.

        cs.Pop.Pop.Pop

    Loop

    If lastMatchEnd < Input.Length Then cs.Append(Input.SubString(lastMatchEnd))

    Return cs

End Sub



Sub MarkRoute(Input As String, Pattern As String, GroupNumber As Int) As CSBuilder

    Dim cs As CSBuilder

    cs.Initialize

    Dim lastMatchEnd As Int = 0

    Dim m As Matcher = Regex.Matcher(Pattern, Input)

  

    Do While m.Find

        Dim currentStart As Int = m.GetStart(GroupNumber)

        Log(GroupNumber)

        Log(currentStart)

        cs.Append(Input.SubString2(lastMatchEnd, currentStart))

      

        Dim AA As String = Input.SubString2(lastMatchEnd, currentStart)

        Log(AA)

        lastMatchEnd = m.GetEnd(GroupNumber)

        Log(lastMatchEnd)

          

        'apply styling here

        cs.Underline

        'cs.Color(0xFF6B8E23)

        cs.Color(0xFFD1650B)

        cs.Clickable("cs", m.Group(GroupNumber))

        cs.Append(m.Group(GroupNumber))

        cs.Pop.Pop.Pop 'number should match number of stylings set.

    Loop

    If lastMatchEnd < Input.Length Then cs.Append(Input.SubString(lastMatchEnd))

    Return cs

End Sub
please help
 
Last edited:
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drgottjr

Expert
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Longtime User
you keep doing the same thing:
B4X: 
Dim s As String = edtDose.Text
Dim cs As CSBuilder = MarkPattern(s, "\B(℗\w+)\b", 1)   ' <<<<< THIS ONE IS OVERWRITTEN BY THE NEXT ONE
edtDose.Text = cs
Dim y As String = edtDose.Text
Dim cs As CSBuilder = MarkRoute(y, "\B:)\w+)\b", 1)     ' <<<<<< THIS ONE OVERWRITES THE PREVIOUS ONE
edtDose.Text = cs                                                            ' <<<<<< FIRST CS IS GONE BECAUSE YOU OVERWROTE IT

you are declaring 2 instances of csbuilder: #2 overwrites #1
have markpattern() and markroute() return a string. then do what i showed previously:
B4X: 
dim cs as csbuilder
cs.initialize
cs.append(MarkPattern(s, "\B(℗\w+)\b", 1) ).append( MarkRoute(y, "\B:)\w+)\b", 1))
edtdose.text = cs.tostring


and please use the code tags when posting code
 
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P

Pathrose

Member
Licensed User
 
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P

Pathrose

Member
Licensed User
Thanks for your reply..
I don't think it works. It only appends the string, no color. Below is my code as suggested by you..please correct
B4X: 
Dim s As String = edtDose.Text
    Dim cs As CSBuilder
    cs.initialize
    cs.append(MarkPattern(s, "\B(℗\w+)\b", 1) ).append( MarkRoute(s, "\B(:\w+)\b", 1))
    edtDose.text = cs.ToString
 
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drgottjr

Expert
Licensed User
Longtime User
i don't lose the colors. try this way:

B4X: 
Dim label1 As Label
label1.Initialize("lbl")
Activity.AddView(label1,0%x,0%y,100%x,20%y)
Dim cs1 As CSBuilder
Dim cs2 As CSBuilder

cs1 = do1
cs2 = do2
' TWO WAYS:
'label1.Text = cs1.Append(cs2)
' OR
'label1.Text = cs1.Append(do2)
' either way works
' even this works:
' label1.Text = do1.Append(do2)

       

Sub do1 As CSBuilder
    Dim cstmp As CSBuilder
    cstmp.Initialize
    cstmp.Color(Colors.Green).Append("hello ").Pop
    Return cstmp  
End Sub

Sub do2 As CSBuilder
    Dim cstmp2 As CSBuilder
    cstmp2.Initialize
    cstmp2.Color(Colors.red).Append("good-bye").Pop
    Return cstmp2
   
End Sub

leave your subs the way they way (return cs).
note: it was definitely a mistake to overwrite 1 csbuilder with another. i hope that is clear. you append the 2nd cs to the 1st. you can either append the 2 csbuilder objects or the 2 subs (since they return a csbuilder).

i cannot comment on the code in your 2 subs. if you are still losing the color change, there may be a problem in the subs. i really have no way of testing that.
 
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