Android Question ContentResolver - openInputStream is missing

[Alexander Stolte]

Hey,

i found on stackoverflow this thread:

Android: Getting a file URI from a content URI?

In my app the user is to select an audio file which the app then handles. The problem is that in order for the app to do what I want it to do with the audio files, I need the URI to be in file form...

stackoverflow.com

The first answer is, to use the ContentResolver.openinputstream:

https://developer.android.com/reference/android/content/ContentResolver.html#openInputStream(android.net.Uri)

Why is this missing in B4A?

 

[Erel]

This is equivalent to:

File.OpenInput(Dir, File) 'in ContentChooser event.

It has nothing to do with getting a file URI.

 

[Alexander Stolte]

'in ContentChooser event.

so?

Dim cc As ContentChooser
cc.Initialize("cc")
cc.Show("*/*", "Select file to be upload.")
wait for cc_Result (Success As Boolean, Dir As String, FileName As String)   
File.OpenInput(Dir, FileName) 'in ContentChooser event.

 

[Alexander Stolte]

Yes its working. thanks