Android Question Doing Min() and Max() at the same time?

agraham

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• Feb 17, 2022

• #2

Are those percentage values integers or doubles? It matters as you have a 'dead band' from 0 to 0.999999.... in your comparison. ?

 

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klaus

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• Feb 17, 2022

• #3

Maybe this:

B4X:

percentage = Min(Max(percentage, 0), 1)

 

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M

Mahares

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• Feb 17, 2022

• #4

How about another variant:

B4X:

Log(IIf( percentage < 0, 0, IIf(percentage > 1, 1, percentage)))

 

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agraham

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• Feb 17, 2022

• #5

@klaus suggestion is correct only for integer values. @Mahares is the same as the original post for both integer and double values.

 

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S

Spavlyuk

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• Feb 17, 2022

• #6

agraham said:

@klaus suggestion is correct only for integer values.

Click to expand...

What do you mean?

B4X:

Dim P As Double = 0.99
Log(Min(Max(P, 0), 1)) ' Logs 0.99

 

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klaus

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• Feb 17, 2022

• #7

agraham said:

@klaus suggestion is correct only for integer values.

Click to expand...

Sorry, but this is wrong.
Min and Max work with Doubles !
I tested it before posting.

From the help:

 

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agraham

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• Feb 17, 2022

• #8

Perhaps I misunderstood the original requirement. I assumed that the actual requirement was for percentage to end up with a value of either 0 or 1. The original code in the first post would do that for integer values but not doubles. It would leave it unchanged for the values from 0 to 0.99999.... That is why I asked for clarification in post #2.

 

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