File.OpenOutput 'too many parameters'

khaleel

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Why do I get this error when I use jOkHttpUtils2 for File.OpenOutput Function ????
While It's documentation states it needs three parameters !

upload_2017-4-9_10-22-30.png
 
Last edited:

khaleel

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Whops.
I missed that it's a method.
thanks anyway !!!
 

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