Android Question How to write this in b4a code ?

[Oke]

hi, how to write this in b4a code, thanks

OkHttpClient client = new OkHttpClient();

Request request = new Request.Builder()
.url("https://api.send.com/starter/province?id=12")
.get()
.addHeader("key", "your-api-key")
.build();

Response response = client.newCall(request).execute();

and

OkHttpClient client = new OkHttpClient();

MediaType mediaType = MediaType.parse("application/x-www-form-urlencoded");
RequestBody body = RequestBody.create(mediaType, "origin=501&destination=114&weight=1700&courier=goexpress");
Request request = new Request.Builder()
.url("https://api.send.com/starter/cost")
.post(body)
.addHeader("key", "your-api-key")
.addHeader("content-type", "application/x-www-form-urlencoded")
.build();

Response response = client.newCall(request).execute();

 

[Erel]

Start here: https://www.b4x.com/android/forum/threads/b4x-okhttputils2-with-wait-for.79345/#content

Job.Download("first url")
Job.GetRequest.SetHeader("key", "your api")

Job.PostString("second url", "origin=501&destination=114&weight=1700&courier=goexpress")
Job.GetRequest.SetHeader("key", "...")
Job.GetRequest.SetContentType("application/x-www-form-urlencoded")

 

[Oke]

Thx Erel...this is very helpful

 

[Oke]

Hi Erel.... I can't find the second url, how do I fix it ?

 

[DonManfred]

I can't find the second url, how do I fix it ?

Give another URL there? It was juts an example...

 

[Oke]

Give another URL there? It was juts an example...

thanks DonManfred, I understand...