Hi All, I am trying to convert an Android App I have finished some time ago, specifically the following part:
I use this code to figure out if the orientation is less or equals to zero and the following code, to draw a line inside a square which moves up and down, sort of like a bubble Level.
The part I am concerned about is the first part of the code above, is there a way to get the orientation from the iOS device just like with the Android code above?
Thanks,
Walter
B4X:
Case se.TYPE_ORIENTATION
magValues = Values
Log("magValues(0): " & magValues(0))
Log("magValues(1): " & magValues(1))
Log("magValues(2): " & magValues(2))
Dim rotationMatrix(0) As Float
If accValues.Length = 0 Or magValues.Length = 0 Then Return
Dim R(9), I(9) As Float
Dim success As Boolean = sm.RunMethod("getRotationMatrix", Array(R, I, accValues, magValues))
If success Then
Dim orientation(3) As Float
sm.RunMethod("getOrientation", Array(R, orientation))
'''Log("orientation: " & (orientation(0) * 180 / cPI + 360) Mod 360))
''' Log("orientation(0): " & orientation(0))
''' Log("orientation(1): " & orientation(1))
''' Log("orientation(2): " & orientation(2))
orientation2 = (orientation(0) * 180) / (cPI + 360)
'''Log("orientation: " & orientation2)
End If
'''Log("values(0): " & Values(0) & " values(1): " & Values(1) & " values(2): " & Values(2))
End SelectI use this code to figure out if the orientation is less or equals to zero and the following code, to draw a line inside a square which moves up and down, sort of like a bubble Level.
B4X:
If orientation2 <= 0 Then
canvasY.DrawLine(0, Normalize(thetaX, 90, 0), canvasY.Bitmap.Width, Normalize(thetaX, 90, 0), Colors.green, 2dip)
limit = Normalize(thetaX, 90, 0)
Else
canvasY.DrawLine(0, (Abs(Normalize(thetaX, 200, 100))+100), canvasY.Bitmap.Width, (Abs(Normalize(thetaX, 200, 100))+100), Colors.Green, 2dip)
limit = (Abs(Normalize(thetaX, 200, 100))+100)
End IfThe part I am concerned about is the first part of the code above, is there a way to get the orientation from the iOS device just like with the Android code above?
Thanks,
Walter
