Android Question Show progress of upload file

[Blue.Sky]

Hi
I use PostString to upload file example below code
How can i show progressing of send file

    ht.Initialize("upload",Module)
    ht.PostString(Library.WebService & "/upload_file",su.EncodeBase64(ou.ToBytesArray))
    ext = getFileExtension(sFile)
    stype = getFileType(ext)
    ht.GetRequest.SetContentType(stype)
    ht.GetRequest.SetHeader("key1",Library.LoginSession.Username)
    ht.GetRequest.SetHeader("key2",Library.LoginSession.Password)
    ht.GetRequest.SetHeader("key3",Library.phone1.GetDeviceId)
    ht.GetRequest.SetHeader("key4",Library.LoginSession.Token)
    ht.GetRequest.SetHeader("path",sParentPath)
    ht.GetRequest.SetHeader("name",Library.GetFilename(sFile))
    ht.GetRequest.SetHeader("extension",ext)

And i php i get file with below code

        $content = base64_decode(file_get_contents("php://input"));
        $len = strlen($content);
        $headers = apache_request_headers();
        
        foreach ($headers as $header => $value) {
            if ($header == "key1")
                $username = $value;
            if ($header == "key2")
                $password = $value;
            if ($header == "key3")
                $dev_id = $value;
            if ($header == "key4")
                $token = $value;
            if ($header == "extension")
                $ext = $value;
            if ($header == "name")
                $name = $value;
            if ($header == "path")
                $path = $value;
        }

 

[Erel]

You will need to use HttpUtils2 source code. Modify PostFile and use CountingInputStream from the RandomAccessFile:

CountingStream.Initialize(in)
req.InitializePost(Link, CountingStream, Length)

CountingStream should be a global variable.

Now you can use a timer to monitor the progress by checking the value of CountintStream.Count

 

[Blue.Sky]

You will need to use HttpUtils2 source code. Modify PostFile and use CountingInputStream from the RandomAccessFile:

CountingStream.Initialize(in)
req.InitializePost(Link, CountingStream, Length)

CountingStream should be a global variable.

Now you can use a timer to monitor the progress by checking the value of CountintStream.Count

Thank you but i cannot change PostString(upload) to PostFile
Cannot i shpw progress in PostString?

 

[Erel]

How large is the string? Unless the string is huge then the progress will not be very meaningful.

 

[Blue.Sky]

How large is the string? Unless the string is huge then the progress will not be very meaningful.

I programming app that upload any file to host.
maybe large or maybe small

 

[DonManfred]

Thank you but i cannot change PostString(upload) to PostFile
Cannot i shpw progress in PostString?

you can try to use this (untested!)

Activity or starter

Sub Process_Globals
    Dim cs As CountingInputStream
End Sub

httpjob.bas

Public Sub PostBytes(Link As String, Data() As Byte)
    Dim in As InputStream
    in.InitializeFromBytesArray(Data,0,Data.Length)
    Main.cs.Initialize(in)
    req.InitializePost(Link, Main.cs, Data.Length)
  
    'req.InitializePost2(Link, Data)
    CallSubDelayed2(HttpUtils2Service, "SubmitJob", Me)
End Sub

 

[Blue.Sky]

you can try to use this (untested!)

Activity or starter

Sub Process_Globals
    Dim cs As CountingInputStream
End Sub

httpjob.bas

Public Sub PostBytes(Link As String, Data() As Byte)
    Dim in As InputStream
    in.InitializeFromBytesArray(Data,0,Data.Length)
    Main.cs.Initialize(in)
    req.InitializePost(Link, Main.cs, Data.Length)
 
    'req.InitializePost2(Link, Data)
    CallSubDelayed2(HttpUtils2Service, "SubmitJob", Me)
End Sub

It test it and correctly worked.Thank you