Android Question Failed uploading image to online server

microbox · Feb 16, 2020

Hi everyone...I getting no where with the application I'm working. I'm trying to upload image to the server but failed to do so. Kindly check my codes below.
ImageToSave is the variable that holds the converted image

B4X:

Sub Camera1_PictureTaken (Data() As Byte)

        camera1.StartPreview
        '-------------------------------------------------------------
        Dim fileName,pma,pmb As String
        DateTime.DateFormat = "yyyy-MM-dd"
        pma = DateTime.Date(DateTime.Now)
        DateTime.TimeFormat = "HH:mm"
        pmb = DateTime.Time(DateTime.Now)
        fileName = "Photo_" & TransId & pma &"_" & pmb
Try    
        '------------------------------------------------------------
        Dim out As OutputStream
        out = File.OpenOutput(File.DirRootExternal & "/" & AppFolder, fileName & ".jpg", False)
        out.WriteBytes(Data, 0, Data.Length)
        out.Close
    Dim im As Bitmap 
    im.Initialize(File.DirRootExternal & "/" & AppFolder,fileName & ".jpg")
    imgphoto.SetBackgroundImage(LoadBitmap(File.DirRootExternal & "/" & AppFolder,fileName & ".jpg"))
    Log("Image saved: " & File.Combine(File.DirRootExternal & "/" & AppFolder, fileName & ".jpg"))
    File1 = File.DirRootExternal & "/" & AppFolder
    File2 = fileName & ".jpg"
    btnCamera.Enabled = True
    Dim bytes() As Byte =  ImageToBytes(im)
    Dim B64 As Base64
    ImageToSave=""
    ImageToSave = B64.EncodeBtoS(bytes,0,bytes.Length-1)
    Log(ImageToSave.Length)
    
Catch
Log("Camera error")
End Try
End Sub

The next block of code is sending to the server

B4X:

Sub btnsendImages_Click
    Dim loginServer As HttpJob
    loginServer.Initialize("SubmitImage",Me)
    loginServer.Download2("http://" & ServerIP,    Array As String("action","SubmitImage","photo",ImageToSave,"rep_id",Rep_Id))
End Sub

The total length of ImageToSave is 1957536 and I'm getting a "414 Request-URI Too long". I read from forum that with this kind of case it is best to use POST. Can any one help me point in the right direction how to resolve my trouble?

Best regards,
microbox

DonManfred · Feb 16, 2020

Try it like this

B4X:

    Dim j As HttpJob
    j.Initialize("",Me)
    j.PostMultipart("https://domain.com",CreateMap("action":"SubmitImage","rep_id":Rep_Id,"photo":ImageToSave),Null)
    Wait For (j) JobDone(j As HttpJob)
    If j.Success Then
        Dim res As String = j.GetString()
        Log(res)
    Else
        Log(j.ErrorMessage)
    End If
    j.Release

microbox · Feb 16, 2020

DonManfred said:

Try it like this

B4X:

    Dim j As HttpJob
    j.Initialize("",Me)
    j.PostMultipart("https://domain.com",CreateMap("action":"SubmitImage","rep_id":Rep_Id,"photo":ImageToSave),Null)
    Wait For (j) JobDone(j As HttpJob)
    If j.Success Then
        Dim res As String = j.GetString()
        Log(res)
    Else
        Log(j.ErrorMessage)
    End If
    j.Release

Hi Don thanks for the time, I tried but I'm having this error message

B4X:

ResponseError. Reason: javax.net.ssl.SSLHandshakeException: javax.net.ssl.SSLProtocolException: SSL handshake aborted: ssl=0x79320858: Failure in SSL library, usually a protocol error
error:1407742E:SSL routines:SSL23_GET_SERVER_HELLO:tlsv1 alert protocol version (external/openssl/ssl/s23_clnt.c:744 0x73edfcfc:0x00000000), Response:
javax.net.ssl.SSLHandshakeException: javax.net.ssl.SSLProtocolException: SSL handshake aborted: ssl=0x79320858: Failure in SSL library, usually a protocol error
error:1407742E:SSL routines:SSL23_GET_SERVER_HELLO:tlsv1 alert protocol version (external/openssl/ssl/s23_clnt.c:744 0x73edfcfc:0x00000000)

JohnC · Feb 17, 2020

Hi, in the sample code you provided, you used "http". But Don's suggested code used "https".

The second error you reported was related to SSL, so maybe you accidently used "https" when using Don's sample and maybe that error is due to the remote website not supporting SSL.

If so, then maybe try Don's code but use http instead of https?

microbox · Feb 17, 2020

B4X:

Dim loginServer As HttpJob
loginServer.Initialize("SubmitImage",Me)
loginServer.PostMultipart("http://" & ServerIP,CreateMap("action":"SubmitImage","rep_id":Rep_Id,"photo":ImageToSave),Null)
Wait For (loginServer) JobDone(loginServer As HttpJob)
    If loginServer.Success Then
        Dim res As String = loginServer.GetString()
        Log(res)
    Else
        Log(loginServer.ErrorMessage)
    End If
    loginServer.Release

when I change https:// to http:// do not gives the ssl error but
log(res) --> gives out NULL

microbox · Feb 17, 2020

@JohnC thanks

here is my code in the php file

B4X:

 case "SubmitImage":
        $id = $_GET["rep_id"]; < -- not sure if this is right.
        $photo = $_GET["photo"]; < -- same.
      
        $q = mysqli_query($con,"Insert into t_photos(rep_id,image)values('$id','$photo')");
         if ($con->query($q) === True) {
            echo "SuccessSavingImage";
            } else {
                echo "Failed to save" . $conn->error;
            }
        break;

JohnC · Feb 17, 2020

microbox said:
when I change https:// to http:// do not gives the ssl error but
log(res) --> gives out NULL

You have a "Log()" line of code for both Success = true or false, so when you say it is reporting NULL, which branch was reporting this (Succeed=True or False branch)?

I'm not a PHP expert, but the code Don provided I believe should work, so I would think the issue is in the PHP if it still doesn't work.

microbox · Feb 17, 2020

@JohnC
not yet saving to the record table, I assumed it did not reached to sql query statement in the php file.

drgottjr · Feb 17, 2020

loginServer.Download2("http://" & ServerIP, Array As String("action","SubmitImage","photo",ImageToSave,"rep_id",Rep_Id))
The total length of ImageToSave is 1957536 and I'm getting a "414 Request-URI Too long". I read from forum that with this kind of case it is best to use POST. Can any one help me point in the right direction how to resolve my trouble?

just so you understand, there are 2 issues:
1) ImageToSave is a string of bytes 1957536 bytes in length. the URI cannot be longer than 2048 bytes. hence the error.
2) furthermore, even if ImageToSave was very small, your Download2() may not have worked. The server may have been expecting a post, not a get (which is what download2() is. and it stands to reason that if the upload involves an image, there is really no way you could use download() and expect it to be a legal URI.

you're getting help with post, and i'm sure it will work out for you, but i just wanted to make sure you understand the importance of giving the server what it's expecting and the way in which it's expecting it.

microbox · Feb 17, 2020

Changing the code in the php to this.
$id = $_POST["rep_id"];
$photo = $_POST["photo"];

Thanks everyone for helping me out...I got it working based from the inputs of @DonManfred, @JohnC and @drgottjr. Finally...time to move on.

JohnC · Feb 17, 2020

Any chance you can post the B4A "sending" code and the PHP "receiving" code so it can be helpful to others who are looking for a similar solution?

microbox · Feb 17, 2020

@JohnC
Okay sure...I will post within today.

DonManfred · Feb 17, 2020

microbox said:
$_GET["rep_id"];

The values are in $_POST!

nazilabdulla · Mar 2, 2020

microbox said:
Changing the code in the php to this.
$id = $_POST["rep_id"];
$photo = $_POST["photo"];

Thanks everyone for helping me out...I got it working based from the inputs of @DonManfred, @JohnC and @drgottjr. Finally...time to move on.

can u please post both PHP and B4A Code ?

microbox · Mar 3, 2020

Hi..I'm sorry it took me awhile to post this...was busy some other things.

and I apologize if my prototype code is not totally cleaned.
Section For the PHP (Receiving)

PHP:

<?php
error_reporting(0);
$host = "localhost";
$user = "root";
$pw = "";
$db = "empprofilr";

$con = mysqli_connect($host,$user,$pw) or die(mysql_error());
mysqli_select_db($con,$db) or die(mysqli_error());
mysqli_query($con,"SET CHARACTER SET utf8");
mysqli_query($con,"SET NAMES 'utf8'");

$action = $_GET["action"];
switch ($action)

{
    case "SaveImage":
        $photo = $_GET["image"];
        $q = mysqli_query($con,"Insert into employees(name,img)values('Test','$photo')");
         if ($con->query($q) === TRUE) {
            echo "Error Saving";
        } else {
            echo "SuccessSave" . $conn->error;
        }
     
    break;
    default:
        die("NULL");

}
?>

This is for the taking picture and converting it.

B4X:

Sub Camera1_PictureTaken (Data() As Byte)
        camera1.StartPreview
        Dim fileName,pma,pmb As String
        DateTime.DateFormat = "yyyy-MM-dd"
        pma = DateTime.Date(DateTime.Now)
        DateTime.TimeFormat = "HH:mm"
        pmb = DateTime.Time(DateTime.Now)
        fileName = "Photo_" & TransId & pma &"_" & pmb
Try  
       
        '------------------------------------------------------------
        Dim out As OutputStream
        out = File.OpenOutput(File.DirRootExternal & "/" & AppFolder, fileName & ".jpg", False)
        out.WriteBytes(Data, 0, Data.Length)
        out.Close
    Dim im As Bitmap
    im.Initialize(File.DirRootExternal & "/" & AppFolder,fileName & ".jpg")
    imgphoto.SetBackgroundImage(LoadBitmap(File.DirRootExternal & "/" & AppFolder,fileName & ".jpg"))
    Log("Image saved: " & File.Combine(File.DirRootExternal & "/" & AppFolder, fileName & ".jpg"))
    File1 = File.DirRootExternal & "/" & AppFolder
    File2 = fileName & ".jpg"
    btnCamera.Enabled = True
        ImageToSave = Base64Con.EncodeFromImage(File1,File2)
        Log("File Saved")
        Msgbox("File saved!","Test It")
Catch
Log("Camera error")
End Try
End Sub

This part is to send to the PHP

B4X:

Sub btnsendImages_Click
    Dim loginServer As HttpJob
    loginServer.Initialize("SubmitImage",Me)
'    loginServer.Download2("http://" & ServerIP ,    Array As String("action","SubmitImage","photo",ImageToSave,"rep_id",Rep_Id))
    loginServer.PostMultipart("http://" & ServerIP,CreateMap("action":"SubmitImage","rep_id":Rep_Id,"photo":ImageToSave.Trim),Null)
    Wait For (loginServer) JobDone(loginServer As HttpJob)
    If loginServer.Success Then
        Dim res As String = loginServer.GetString()
        If res.Contains("SuccessSavingImage") Then
            Log("Image and id saved!")  
        End If
    Else
        Log(loginServer.ErrorMessage)
    End If
    loginServer.Release
End Sub

Android Question Failed uploading image to online server

microbox

Active Member

DonManfred

Expert

microbox

Active Member

JohnC

Expert

microbox

Active Member

microbox

Active Member

JohnC

Expert

microbox

Active Member

drgottjr

Expert

microbox

Active Member

JohnC

Expert

microbox

Active Member

DonManfred

Expert

nazilabdulla

Member

microbox

Active Member

Similar Threads