Dim N1 As Float =345.34567
Dim s As String = NumberFormat(N1, 1, 2)
Log(s) '345.35
Dim s As String =NumberFormat2(N1,1,2,2,False)
Log(s) '345.35
Dim s As String = NumberFormat(Ceil(N1*100)/100, 1, 2)
Log(s) '345.35
Dim s As String = NumberFormat(Floor(N1*100)/100, 1, 2)
Log(s) '345.34 ' here is the answer the OP wants
try something like this
Log(InteroDecimale("345.34567",".",2)) ' 345.34
B4X:
Sub InteroDecimale(Numero As String,Separatore As String,Decimali As Int) As String
'numero = 12345.6789
Dim FormattoNUmero As List =Regex.Split("\" & Separatore, Numero)
Dim ritorno As String
ritorno=FormattoNUmero.Get(0)
If Decimali > 0 Then
ritorno = ritorno & Separatore & Left(FormattoNUmero.Get(1),Decimali)
End If
Return ritorno
End Sub
Sub Left(Text As String, Length As Int)As String
If Length>Text.Length Then Length=Text.Length
Return Text.SubString2(0, Length)
End Sub